The concept of angle bisector is very important in geometry. Especially while learning geometry including triangles. In this section, we will learn angle bisector concepts and angle bisector theorem.

**Angle Bisector**

*“An angle bisector is a ray or a line that divides an angle into two equal angles.”*Let us look at the figure,

∠AOB is an angle and ray \overrightarrow{OC}

divides ∠AOB in such a way that

m∠AOC = m∠COB

and hence \overrightarrow{OC} is the angle bisector of ∠AOB.

This is because \overrightarrow{OC} divides ∠AOB into two equal angles.

For example,

Here,

∠AOB = 60º

And ray \overrightarrow{OC} divides it into two equal angles,

∠AOC = ∠COB = 30º

So, \overrightarrow{OC} is the angle bisector.

**Properties of an angle bisector**

- In a triangle,
**the angle bisector of any angle will divide the opposite side in the ratio of the sides containing the angle. This is also called ANGLE BISECTOR THEOREM of a triangle.**

In ΔABC,

AD is the angle bisector, such that ∠BAD = ∠CAD,

Then according to the angle bisector theorem,

Angle bisector of any angle will divide the opposite side in the ratio of the sides containing the angle.

Here,

AD is the angle bisector, Sides AB and AC are containing the angle bisector.

BC is the opposite side and D divides it into two parts BD and DC,

So, according to the Angle bisector theorem.

**\frac{BD}{DC}=\frac{AB}{AC}**

**Angle Bisector Theorem Proof**

In a triangle, **the angle bisector of any angle will divide the opposite side in the ratio of the sides containing the angle.**

* Given – *In ΔABC,

AD is the angle bisector, such that ∠BAD = ∠CAD .

*\frac{BD}{DC}=\frac{AB}{AC}*

To Prove –To Prove –

* Construction – *Draw DA || CE to meet BA produced at E.

* Proof – *Let,

∠BAD = ∠CAD = x

As DA || CE and line AC is the transversal, then

∠DAC = ∠ACE = x { Alternate interior angles } …….(i)

& ∠BAD = ∠BEC = x { Corresponding Angles } …….(ii)

Comparing equation (i) and (ii), we get

∠ACE = ∠AEC = x

Now, in ΔAEC,

As ∠ACE = ∠AEC = x

then AC = AE { Sides opposite to equal angles are equal } ……..(iii)

Now, in ΔBEC, As AD||EC

then by Thales theorem,

\frac{BD}{DC}=\frac{BE}{AE} ……..(iv)

From equation (iii) AE = AC,

then putting this value in equation (iv)

\frac{BD}{DC}=\frac{AB}{AC}

Hence proved.

2. ** Any point on the angle bisector is at an equal distance from both arms of the angle.**You may also want to learn –